Answer
a) $T_{i}=158.83^{\circ}C$
b) $m_{t}=7.393kg$
c) $V_{f}=2.603m^3$
d) Show in the image
Work Step by Step
a) From table A-5:
$T_{i}=158.83^{\circ}C$
b) Knowing that $m=\frac{V}{\upsilon}$
From table A-5:
$m_{f}=\frac{0.005m^3}{0.001101\frac{m^3}{kg}}=4.541kg$
$m_{g}=\frac{0.9m^3}{0.3156\frac{m^3}{kg}}=2.852kg$
$m_{t}=m_{f}+m_{g}=4.541kg +2.852kg=7.393kg$
c)As $T\gt T_{sat}$ is a superheated vapor
From table A-6:
$\upsilon_{f}=0.35212\frac{m^3}{kg}$
$V_{f}=\frac{m_{t}}{\upsilon_{f}}=\frac{7.393kg}{0.35212\frac{m^3}{kg}}=2.603m^3$
