Answer
$T=202.97^{\circ}C$
See the image to the process on a T-v diagram
Work Step by Step
$\upsilon=\frac{V}{m}=\frac{1.8m^3}{15kg}=0.12\frac{m^3}{kg}$
$x_{2}=1$
Interpolating from table A-4:
$T=202.97^{\circ}C$
Thermodynamics: An Engineering Approach 8th Edition
by Cengel, Yunus; Boles, Michael
Published by
McGraw-Hill Education
ISBN 10:
0-07339-817-9
ISBN 13:
978-0-07339-817-4
Chapter 3 - Properties of Pure Substances - Problems - Page 154: 3-50
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