Thermodynamics: An Engineering Approach 8th Edition

Published by McGraw-Hill Education
ISBN 10: 0-07339-817-9
ISBN 13: 978-0-07339-817-4

Chapter 3 - Properties of Pure Substances - Problems - Page 154: 3-48

Answer

$T=106.22^{\circ}C$

Work Step by Step

First we calculated the pression exerted by the piston: $A=150cm^2*\frac{1m^2}{10000cm^2}=0.015m^2$ $W=mg=40kg*9.81\frac{m}{s^2}=392.4N$ $P=\frac{W}{A}=\frac{392.4N}{0.015m^2}=26.16kPa$ $P_{abs}=100kPa+26.16kPa=126.16kPa$ Interpolating from table A-5: $T=106.22^{\circ}C$
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