Answer
$P=85.4kPa$
Work Step by Step
The amount of heat transfer is:
$Q=2\frac{kJ}{s}*0.75*(30min*\frac{60s}{1min})=2700kJ$
$h_{fg}=\frac{Q}{m}=\frac{2700kJ}{1.19kg}=2268.91\frac{kJ}{kg}$
From table A-5, by trial-error approach:
$P=85.4kPa$
Thermodynamics: An Engineering Approach 8th Edition
by Cengel, Yunus; Boles, Michael
Published by
McGraw-Hill Education
ISBN 10:
0-07339-817-9
ISBN 13:
978-0-07339-817-4
Chapter 3 - Properties of Pure Substances - Problems - Page 154: 3-49
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