Answer
$T_{2}=99.02^{\circ}C$
Work Step by Step
Boiling pressure for $98^{\circ}C$ is:
Interpolating from table A-4
$P_{1}=94.7kPa$
Pressure for $40cm$ deep is:
$P_{2}=94.7+\rho gh=94.7+1000\frac{kg}{m^3}*9.81\frac{m}{s^2}*(0.4m-0.05m)=98.13kPa$
Boiling temperature for $98.13kPa$ is:
Interpolating from table A-5
$T_{2}=99.02^{\circ}C$
