Answer
$T=100.2^{\circ}C$
Work Step by Step
First we calculate the force exerted by the lid:
$A=\frac{\pi D^2}{4}=\frac{\pi*(0.2m)^2}{4}=0.031415m^2$
$W=mg=4kg*9.81\frac{m}{s^2}=39.24N$
$P=\frac{W}{A}=\frac{39.24N}{0.031415m^2}=1.25kPa$
$P_{abs}=101kPa+1.25kPa=102.25kPa$
Interpolating from table A-5:
$T=100.2^{\circ}C$
