Answer
$\frac{1}{32}$
Work Step by Step
During every half-life, the number of radioactive atoms in the pure sample is multiplied by one-half.
$$\frac{N}{N_o}=(\frac{1}{2})^n=(\frac{1}{2})^5 $$
$$=\frac{1}{32} =3.125\%$$
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