Answer
$9\times10^{-16}m$.
Work Step by Step
Find the spacing using equation 17–8, the capacitance of a parallel-plate capacitor.
$$C=\frac{\epsilon_oA}{d}$$
$$d=\frac{\epsilon_o A}{C}=\frac{(8.85\times10^{-12}C^2/(N\cdot m^2)) (0.0001m^2)}{1F}$$
$$=9\times10^{-16}m$$
This spacing is unrealistically small, less than a nuclear radius, so an 1-F air gap capacitor is impractical.
