Answer
0.24 square meters
Work Step by Step
Combine equations 17–7 and 17–8 and find the area.
$Q=CV$ and $C=\frac{\epsilon_oA}{d}$
$$ Q=\frac{\epsilon_oA}{d}V$$
The desired electric field is V/d for the capacitor.
$$Q=\epsilon_o(A)(E)$$
$$A=\frac{Q}{(\epsilon_o)(E)}$$
$$A=\frac{4.2\times10^{-6}C}{(8.85\times10^{-12}C^2/(N\cdot m^2)) (2000000V/m)}$$
$$A=0.24m^2$$
