Answer
$6.00\times10^{-5}C$
Work Step by Step
Assume that the capacitor is fully charged, and find the charge using equation 17–7, Q=CV.
$$Q=CV=(5.00\times10^{-6}F)(12.0V)= 6.00\times10^{-5}C$$
Physics: Principles with Applications (7th Edition)
by Giancoli, Douglas C.
Published by
Pearson
ISBN 10:
0-32162-592-7
ISBN 13:
978-0-32162-592-2
Chapter 17 - Electric Potential - Problems - Page 497: 37
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