Answer
$8.5\times10^{-30}C \cdot m$
Work Step by Step
As stated on page 482, the dipole moment is the product of the magnitude of one of the charges, and the separation distance.
$$p=Q\mathcal{l}=(1.60\times10^{-19}C)(0.53\times10^{-10}m)$$
$$=8.5\times10^{-30}C \cdot m$$
