Answer
$7.2\times10^7m^2$
Work Step by Step
Find the area using equation 17–8, the capacitance of a parallel-plate capacitor.
$$C=\frac{\epsilon_oA}{d}$$
$$A=\frac{Cd}{\epsilon_o }=\frac{(0.20F)(0.0032m)}{8.85\times10^{-12}C^2/(N\cdot m^2)}$$
$$=7.2\times10^7m^2$$
This is unrealistically large, so an air gap capacitor is impractical.
