Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson
ISBN 10: 0133942651
ISBN 13: 978-0-13394-265-1

Chapter 35 - Optical Instruments - Exercises and Problems - Page 1017: 8

Answer

$D = 3.0~mm$

Work Step by Step

Note that f-number is $\frac{f}{D}$ We can find the aperture diameter $D$: $f-number = \frac{f}{D}$ $D = \frac{f}{f-number}$ $D = \frac{12~mm}{4.0}$ $D = 3.0~mm$
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