Answer
The height of the image is $~~3.0~mm$
Work Step by Step
We can find the height of the image:
$h' = M~h$
$h' = (-\frac{f}{s})(h)$
$h' = (-\frac{0.015~m}{10~m})(2.0~m)$
$h' = -0.0030~m$
$h' = -3.0~mm$
The height of the image is $~~3.0~mm$
Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)
by Knight, Randall D.
Published by
Pearson
ISBN 10:
0133942651
ISBN 13:
978-0-13394-265-1
Chapter 35 - Optical Instruments - Exercises and Problems - Page 1017: 6
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