## Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

The index of refraction of quartz for violet light is $~~1.48$
We can use the red light to find the incident angle: $n_1~sin~\theta_1 = n_r~sin~\theta_r$ $sin~\theta_1 = \frac{n_r~sin~\theta_r}{n_1}$ $\theta_1 = sin^{-1}~(\frac{n_r~sin~\theta_r}{n_1})$ $\theta_1 = sin^{-1}~(\frac{1.45~sin~26.3^{\circ}}{1.00})$ $\theta_1 = sin^{-1}~(0.64245)$ $\theta_1 = 40^{\circ}$ We can find the index of refraction of quartz for violet light: $n_v~sin~\theta_v = n_1~sin~\theta_1$ $n_v = \frac{n_1~sin~\theta_1}{sin~\theta_v}$ $n_v = \frac{1.00~sin~40^{\circ}}{sin~25.7^{\circ}}$ $n_v = 1.48$ The index of refraction of quartz for violet light is $~~1.48$