Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson
ISBN 10: 0133942651
ISBN 13: 978-0-13394-265-1

Chapter 35 - Optical Instruments - Exercises and Problems - Page 1017: 25

Answer

$L = 55~km$

Work Step by Step

We can write an equation for the resolution: $\theta_{min} = \frac{1.22~\lambda}{D}$ $\theta_{min} = \frac{(1.22)~(600\times 10^{-9}~m)}{0.040~m}$ $\theta_{min} = 1.83\times 10^{-5}~rad$ We can find the distance $L$: $\theta = \frac{d}{L}$ $L = \frac{d}{\theta}$ $L = \frac{1.0~m}{1.83\times 10^{-5}~rad}$ $L = 5.5\times 10^4~m$ $L = 55~km$
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