## Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson

# Chapter 35 - Optical Instruments - Exercises and Problems - Page 1017: 11

#### Answer

(a) Roman is farsighted. (b) His near point without the lenses is $~~0.50~m$

#### Work Step by Step

(a) The prescription has a positive value. This means that the lens is a converging lens. Therefore, Roman is farsighted. (b) We can find the location of the image: $P = \frac{1}{s}+\frac{1}{s'}$ $\frac{1}{s'} = P - \frac{1}{s}$ $\frac{1}{s'} = 2.0~m^{-1} - \frac{1}{0.25~m}$ $\frac{1}{s'} = -2.0~m^{-1}$ $s' = -0.50~m$ His near point without the lenses is $~~0.50~m$

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