Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson
ISBN 10: 0133942651
ISBN 13: 978-0-13394-265-1

Chapter 35 - Optical Instruments - Exercises and Problems - Page 1017: 23


$\lambda_2 = 1.58\times 10^{-6}~m$

Work Step by Step

The effect of scattering is proportional to $\frac{1}{\lambda^4}$ We can find the wavelength $\lambda_2$ such that the scattering is only $1\%$: $\frac{\lambda_2^4}{\lambda_1^4} = \frac{1}{1/100}$ $\lambda_2^4 = 100~\lambda_1^4$ $\lambda_2 = \sqrt[4] {100}~\lambda_1$ $\lambda_2 = (\sqrt[4] {100})~(500\times 10^{-9}~m)$ $\lambda_2 = 1.58\times 10^{-6}~m$
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