Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 42 - Nuclear Physics - Exercises and Problems - Page 1274: 21

Answer

$4.57\times 10^9~~$ alpha particles are emitted.

Work Step by Step

We can find the number of atoms remaining after $t = 50~min$: $N = N_0~(0.5)^{t/(t_{1/2})}$ $N = (1.0\times 10^{10})~(0.5)^{50/100}$ $N = 7.07\times 10^9$ We can find the number of atoms remaining after $t = 200~min$: $N = N_0~(0.5)^{t/(t_{1/2})}$ $N = (1.0\times 10^{10})~(0.5)^{200/100}$ $N = 2.50\times 10^9$ We can find the number of alpha particles emitted: $(7.07\times 10^9) - (2.50\times 10^9) = 4.57\times 10^9$ $4.57\times 10^9~~$ alpha particles are emitted.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.