Answer
(a) $^3He$ has 2 protons
$^3He$ has 1 neutron
(b) $^{32}P$ has 15 protons
$^{32}P$ has 17 neutrons
(c) $^{32}S$ has 16 protons
$^{32}S$ has 16 neutrons
(d) $^{238}U$ has 92 protons
$^{238}U$ has 146 neutrons
Work Step by Step
(a) $^3He$ has atomic number 2
$^3He$ has 2 protons
Note that $3-2 = 1$
$^3He$ has 1 neutron
(b) $^{32}P$ has atomic number 15
$^{32}P$ has 15 protons
Note that $32-15 = 17$
$^{32}P$ has 17 neutrons
(c) $^{32}S$ has atomic number 16
$^{32}S$ has 16 protons
Note that $32-16 = 16$
$^{32}S$ has 16 neutrons
(d) $^{238}U$ has atomic number 92
$^{238}U$ has 92 protons
Note that $238-92 = 146$
$^{238}U$ has 146 neutrons