Answer
$P = 10~kW$
Work Step by Step
In part (a), we found that the kinetic energy is $3.0\times 10^5~J$
We can find the average power that is required:
$P = \frac{E}{t}$
$P = \frac{3.0\times 10^5~J}{30~s}$
$P = 10~kW$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 8 - Potential Energy and Conservation of Energy - Problems - Page 211: 114b
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
