Answer
He had to transfer $~~3.0\times 10^5~J~~$ of energy.
Work Step by Step
We can estimate that Daniel Goodwin's mass was $70~kg$
We can find the change in gravitational potential energy from the bottom of the building to the top:
$\Delta U = mg~\Delta h$
$\Delta U = (70~kg)(9.8~m/s^2)(443~m)$
$\Delta U = 3.0\times 10^5~J$
He had to transfer $~~3.0\times 10^5~J~~$ of energy.
