Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 8 - Potential Energy and Conservation of Energy - Problems - Page 211: 103a

Answer

The speed at the end of the $~~1.6~s~~$ is $~~8.8~m/s$

Work Step by Step

We can find the acceleration: $x = \frac{1}{2}at^2$ $a = \frac{2x}{t^2}$ $a = \frac{(2)(7.0~m)}{(1.6~s)^2}$ $a = 5.47~m/s^2$ We can find the speed at the end of the $1.6~s$: $v_f = v_0+at$ $v_f = 0+at$ $v_f = (5.47~m/s^2)(1.6~s)$ $v_f = 8.8~m/s$ The speed at the end of the $~~1.6~s~~$ is $~~8.8~m/s$
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