Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 8 - Potential Energy and Conservation of Energy - Problems - Page 211: 109a

Answer

The kinetic energy is $~~2350~J$

Work Step by Step

We can use conservation of energy to find the kinetic energy at the bottom: $K_f+U_f = K_0+U_0$ $K_f+0 = 0+U_0$ $K_f = mgh$ $K_f = (60.0~kg)(9.80~m/s^2)(4.00~m)$ $K_f = 2350~J$ The kinetic energy is $~~2350~J$
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