Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 8 - Potential Energy and Conservation of Energy - Problems - Page 211: 102a

Answer

The climber would expend $~~7.8\times 10^6~J~~$ of energy.

Work Step by Step

We can find the change in gravitational potential energy from sea level to the summit of Mount Everest: $\Delta U = U_f-U_0$ $\Delta U = mgh-0$ $\Delta U = (90~kg)(9.8~m/s^2)(8850~m)$ $\Delta U = 7.8\times 10^6~J$ The climber would expend $~~7.8\times 10^6~J~~$ of energy.
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