Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 6 - Force and Motion-II - Problems - Page 141: 19a

Answer

The block will not move.

Work Step by Step

The maximum force of static friction is equal to $$F_{s,max}=\mu_sN$$ Since the normal force is equal to the force on the wall, substitute $N=12N$ and $\mu_s=0.60$ yields a maximum force of static friction of $$F_{s,max}=(0.60)(12N)=7.2N$$ The block weighs $5.0N$. This force is less than the force of static friction, therefore, the object won't move.
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