Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 5 - Force and Motion-I - Problems - Page 121: 62c

Answer

The decrease in launch speed when changing the angle from $30.00^{\circ}$ to $42.00^{\circ}$ is $$\frac{12.76 \mathrm{\ m} / \mathrm{s}-12.54 \mathrm{\ m} / \mathrm{s}}{12.76 \mathrm{\ m} / \mathrm{s}}=0.0169=1.69\ \%$$

Work Step by Step

The decrease in launch speed when changing the angle from $30.00^{\circ}$ to $42.00^{\circ}$ is $$\frac{12.76 \mathrm{\ m} / \mathrm{s}-12.54 \mathrm{\ m} / \mathrm{s}}{12.76 \mathrm{\ m} / \mathrm{s}}=0.0169=1.69\ \%$$
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