Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 5 - Force and Motion-I - Problems - Page 121: 59d


$T=\dfrac {2Mm}{M+mg}=\dfrac {2\times 15\times 10}{15+10}g=12g\approx 117.6N$

Work Step by Step

Let's assume that object is moving downwards with an acceleration a so monkey will be moving upwards with an acceleration $a$ Because length of the rope doesn't change Lets write Newton's Second Law for both monkey and object Assuming mass of the monkey is $m$ $ T-mg=ma\left( 1\right) $ Assuming mass of the object is $M$ $Mg-T=Ma(2)$ From (1) and (2) we get $T=\dfrac {2Mm}{M+mg}=\dfrac {2\times 15\times 10}{15+10}g=12g\approx 117.6N$
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