Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 42 - Nuclear Physics - Problems - Page 1307: 95b

Answer

$\frac{R_0}{R} = 1.184$

Work Step by Step

The factor is given by $\frac{R_0}{R} = e^{\lambda t} = e^{ t ln 2 / T_{1/2}} $ $\frac{R_0}{R} = e^{ (3.48 d) ln 2 /14.28 d } $ $\frac{R_0}{R} = 1.184$
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