Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 42 - Nuclear Physics - Problems - Page 1308: 96a

Answer

See explanation.

Work Step by Step

$N_{210} $ = The amount of Pb Nuclei that changes because of two decay which is 1. Decay from $^{226}Ra $ into $^{210} Pb$ (rate $R_{226} =\lambda_{226} R_{226}$) 2. Decay from $^{210}Pb $ into $^{206} Pb$ (rate $R_{210} = \lambda_{210} R_{210})$ Since the first decay causes $N_{210}$ to increase and second decay causes it to decrease, the equation becomes $\frac{dN_{210}}{dt} = R_{226} - R_{210}$ $\frac{dN_{210}}{dt} = \lambda_{226} R_{226} - \lambda_{210} R_{210} $
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