Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 42 - Nuclear Physics - Problems - Page 1308: 97a

Answer

$\lambda = 4.8\times 10^{-18}~s^{-1}$

Work Step by Step

The sample of uranium has $2.5\times 10^{18}~atoms$ The text says that 12 atoms would decay in 1 second. We can find the disintegration constant: $-\frac{dN}{dt} = \lambda~N$ $\lambda = \frac{-\frac{dN}{dt}}{N}$ $\lambda = \frac{-(-12~atoms/s)}{2.5\times 10^{18}~atoms}$ $\lambda = \frac{12~atoms/s}{2.5\times 10^{18}~atoms}$ $\lambda = 4.8\times 10^{-18}~s^{-1}$
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