Answer
$0.708$
Work Step by Step
Recall that $\frac{N_{226}}{N_{210}} = 70.8$
Since only $1\% $ of the $^{226}Ra$ remains,
So $1\% $ of $70.8$ is
$(0.0100)(70.8) = 0.708$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 42 - Nuclear Physics - Problems - Page 1308: 96e
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