Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 42 - Nuclear Physics - Problems - Page 1307: 92a

Answer

See explanation.

Work Step by Step

If the mass number of 2 radionuclides are given by $4n +k$ and $4n' +k$, then the heavier one can decay into the lighter one by a series of $\alpha$ and $\beta$ decays. This is because radioisotopes doesn't decay directly into a stable state, but rather it forms chain until reaching the most stable isotope. All of the decay products belong to the same family. The mass number, A of a radionuclide changes by 4 in an $\alpha$ decay and is unchanged in a $\beta $ decay. If $A = 4n + k$, then after $\alpha$ decay with time (m), its mass number becomes $A = 4n + k – 4m = 4(n – m) + k$
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