Answer
$A = 27 $
Work Step by Step
For a spherical nucleus with a radius of 3.6 fm, the mass number, A is given by the equation
$A = [\frac{r}{r_o}]^3 $
$A = [\frac{3.6 \times 10^{-15} m }{1.2 \times 10^{-15} m}]^3 $
$A = 27 $
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