Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 42 - Nuclear Physics - Problems - Page 1307: 80a

Answer

$R = 6.92 \times 10^7 /h = 7.0 \times 10^7 /h$ In one hour, $7.0 \times 10^7 $ electrons will intercept.

Work Step by Step

Assuming target area is $1 \space m^2$ $\frac{Target \space rate}{Total \space rate \space upward} = \frac{1 \space m^2}{(2.6 \times 10^5 km^2) (1000 m/km^2)} = 3.846 \times 10^{-12}$ Half beta decay $R= \frac{1}{2} (1 \times 10^{16} /s ) ( 3.846 \times 10^{-12}) = 19230 /s$ To know the rate of decay at one hour, convert R to hour $R = (19230 /s)(3600 s/h) = 6.92 \times 10^7 /h$ $R = 7.0 \times 10^7 /h$ So in one hour, $7.0 \times 10^7 $ electrons will intercept.
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