Answer
$\lambda=4.74m$
Work Step by Step
$\omega=\frac{1}{\sqrt{LC}}$
We plug in the known values to obtain:
$\omega=\frac{1}{\sqrt{(0.253\times 10^{-6})(25\times 10^{-12})}}=3.9762\times 10^8\frac{rad}{s}$
Next, we find the frequency;
$f=\frac{\omega}{2\pi}=\frac{3.9762\times 10^8}{2(3.1416)}=6.328\times 10^7Hz$
Now, we find wavelength using the formula $\lambda=\frac{c}{f}$;
$\lambda=\frac{3\times 10^8}{6.328\times 10^7}=4.74m$
