Answer
$P_{r}=1.4 \times 10^{-22} \mathrm{~W} $
Work Step by Step
The power received is
$$
P_r=\left(1.0 \times 10^{-12} \mathrm{~W}\right) \frac{\pi(300 \mathrm{~m})^2 / 4}{4 \pi\left(6.37 \times 10^6 \mathrm{~m}\right)^2}\\=1.4 \times 10^{-22} \mathrm{~W} .
$$
