Answer
$B_m=2.9\times 10^{-10}T$
Work Step by Step
Using the fact that $E_m=cB_m$, substituting the value of $E_m=8.7\times 10^{-2}N/C$ yields $$B_m=\frac{E_m}{c}=\frac{8.7\times 10^{-2}N/C}{3.0\times10^8m/s}=2.9\times 10^{-10}T$$
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