Answer
$B_{max}=1.07\times 10^{-12}T$
Work Step by Step
We know that;
$B_{max}=\frac{E_{max}}{c}$
We plug in the known values to obtain:
$B_{max}=\frac{3.20\times 10^{-4}}{3\times 10^8}=1.07\times 10^{-12}T$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 33 - Electromagnetic Waves - Problems - Page 1001: 10
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