Answer
$P=1.1 \times 10^{15} \mathrm{~W}$
Work Step by Step
The power of the source would be
$
P=4 \pi r^2 I=4 \pi\left[\left(2.2 \times 10^4 \mathrm{ly}\right)\left(9.46 \times 10^{15} \mathrm{~m} / \mathrm{ly}\right)\right]^2\left\lfloor\frac{1.0 \times 10^{-12} \mathrm{~W}}{4 \pi\left(6.37 \times 10^6 \mathrm{~m}\right)^2}\right\rfloor=1.1 \times 10^{15} \mathrm{~W}
$
