Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 33 - Electromagnetic Waves - Problems - Page 1001: 2b

Answer

213 s

Work Step by Step

In the previous section, we found that the frequency $\nu=4.7\times10^{-3}\,Hz$. Time period T is the inverse of frequency. Therefore, $T=\frac{1}{4.7\times10^{-3}\,Hz}=213\,s$
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