Answer
$B = 10~\mu T$
Work Step by Step
We can find the magnitude of the magnetic field:
$i = \frac{BHv}{R}$
$B = \frac{iR}{Hv}$
$B = \frac{(3.0\times 10^{-6}~A)(0.020~\Omega)}{(0.015~m)(0.40~m/s)}$
$B = 10~\mu T$
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