Answer
$i_S = 3.0~A$
Work Step by Step
In part (g), we found that $i_1 = 2.0~A$
In part (h), we found that $i_2 = 1.0~A$
Since all the current goes through the switch before splitting into two branches, the current $i_s$ is equal to the sum of $i_1$ and $i_2$
Therefore:
$i_S = 3.0~A$
