Answer
2.0 A/s
Work Step by Step
$Ɛ_{L}$= L $\times$ $\frac{dI}{dt}$
=$\frac{Ɛ_{L}}{L}$= $\frac{di_{2}}{dt}$
=$\frac{10V}{5.0H}$
= 2.0 A/s
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