Chapter 30 - Induction and Inductance - Problems - Page 899: 54d

$i_2 = 2.73~A$

In part (c), we found that $i_1 = 4.55~A$ We can find the potential difference across $R_1$: $\Delta V = (4.55~A)(10.0~\Omega) = 45.5~V$ Since the total potential difference across $R_1$ and $R_2$ is $100~V$, the potential difference across $R_2$ must be $54.5~V$ We can find $i_2$: $i_2 = \frac{54.5~V}{20.0~\Omega} = 2.73~A$