Answer
$i = 7.37~mA$
Work Step by Step
We can find $i$:
$i = \frac{\mathscr{E}}{R}~(1-e^{-t/\tau_L})$
$i = \frac{\mathscr{E}}{R}~(1-e^{-1.0~\tau_L/\tau_L})$
$i = \frac{\mathscr{E}}{R}~(1-e^{-1.0})$
$i = \frac{\mathscr{14.0~V}}{1200~\Omega}~(1-\frac{1}{e})$
$i = 7.37~mA$
