Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 30 - Induction and Inductance - Problems - Page 899: 49

Answer

The equivalent inductance is $~~59.3~mH$

Work Step by Step

We can find the equivalent inductance of $L_2$ and $L_3$ which are in parallel: $\frac{1}{L_{23}} = \frac{1}{L_2}+\frac{1}{L_3}$ $\frac{1}{L_{23}} = \frac{1}{50.0~mH}+\frac{1}{20.0~mH}$ $\frac{1}{L_{23}} = \frac{2}{100.0~mH}+\frac{5}{100.0~mH}$ $L_{23} = 14.3~mH$ We can find the equivalent inductance of $L_1, L_{23},$ and $L_4$ which are in series: $L_{eq} = 30.0~mH+14.3~mH+15.0~mH = 59.3~mH$ The equivalent inductance is $~~59.3~mH$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.