Answer
$\phi=2.45mWb$
Work Step by Step
We know that;
$\phi=NAB$
We plug in the known values to obtain:
$\phi=30(3.1416\times (0.10)^2)(2.60\times 10^{-3})=2.45\times 10^{-3}$
Therefore; $\phi=2.45\times 10^{-3}=2.45mWb$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 30 - Induction and Inductance - Problems - Page 899: 41a
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