Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 28 - Magnetic Fields - Problems - Page 830: 28

Answer

$K.E=2.09\times 10^{-22}J$

Work Step by Step

We can determine K.E from the formula: $K.E=\frac{1}{2}mv^2$....................eq(1) The centripetal force is given as $F=\frac{mv^2}{r}$ This means that eq(1) can be re-written as: $K.E=\frac{1}{2}\frac{mv^2}{r}\times r$ $K.E=\frac{1}{2}\times F\times r$ We plug in the known values into this equation to obtain: $K.E=\frac{1}{2}\times 1.60\times 10^{-17}\times 26.1\times 10^{-6}$ $K.E=2.09\times 10^{-22}J$
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