Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 28 - Magnetic Fields - Problems - Page 830: 21c

Answer

$f=13.1 MHz$

Work Step by Step

We can determine the circling frequency from the following formula $f=\frac{qB}{2{\pi}m}$ We plug in the known values to obtain: $f=\frac{1.6\times 10^{-19}(467\times 10^{-6})}{2(3.1416)(9.109\times 10^{-31})}$ $f=13.1\times 10^6$ $f=13.1$ MHz
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